Elite Trending

Happy ‘Bobby Bonilla Day’ to all New York Mets fans

Written on 07/01/2019
Ryan Honey

July 1, 2019 is the ninth annual “Bobby Bonilla Day,” in which the New York Mets pay the former All-Star $1.19 million.

Ryan Honey

Every year on July 1, the baseball world celebrates “Bobby Bonilla Day.” This is the day that the New York Mets pay former MLB All-Star Bobby Bonilla $1.19 million.

I should explain.

In 1999, the Mets released Bonilla after just one season. However, they still owed Bonilla $5.9 million. Bonilla and his agent thus cut a deal with the organization, stating that Bonilla would defer the payment for a decade. The Mets would then have to pay Bonilla $1.19 million every year starting in 2011 and ending in 2035.

Yes, you read that right. A guy that hasn’t played for the Mets in 20 years is still getting more per-year than Pete Alonso is right now.

On Monday, Bonilla will receive his ninth installment of $1,119,248.20, with 16 installments left.

New York Mets

Bonilla played in the majors for 16 years, from 1986-2001. This included two separate stints with the Mets, one from 1992-1995 and the other in 1999. He finished his long career batting .279 with 287 home runs and 1,173 RBIs.

He was selected to six All-Star games in his career, won three Silver Slugger Awards and was a World Series champion in 1997 with the Florida Marlins.

So yes, happy Bobby Bonilla Day for the ninth time. There’s only 16 more!

As for the Mets, it’s probably a day they like to forget every single year. Let’s be real, it’s tough to pay a guy $1.19 million every single July when he hasn’t played for the team in 20 years. Moreover, it’s especially tough when the organization is struggling for any type of positive news lately.

Follow Ryan on TWITTER

FOR FULL STORY ON STANDARD WEBSITE: Happy ‘Bobby Bonilla Day’ to all New York Mets fans | Elite Sports NY